Question

How do you solve `\frac { 3} { 4} b + 5= 14`?

Answer 1

`b=12`

Explanation:

Multiply all terms on both sides of the equation by 4 to eliminate the fraction.

`cancel(4)^1xx(3b)/cancel(4)^1+(4xx5)=(4xx14)`

`rArr3b+20=56`

subtract 20 from both sides.

`3bcancel(+20)cancel(-20)=56-20`

`rArr3b=36`

To solve for b, divide both sides by 3.

`(cancel(3) b)/cancel(3)=36/3`

`rArrb=12" is the solution"`