Question

How do you solve `\frac { 3} { 4} x ^ { 2} + 12= 0`?

Answer 1

There is no Real solution.

Explanation:

Although this is a quadratic equation, it is a special case because there is no term in `x`

`3/4x^2 = -12`

`4/3 xx3/4x^2 = -12xx4/3`

`x^2 = -16`

`x = +-sqrt(-16)`

There is no real solution because the square root of a negative number is an imaginary number. It does not exist.