How do you solve #\frac{3}{4} x - \frac{1}{4} < x - 3#?

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Answer 1 · 2016-09-25T06:49:58

#x > 11#

Solve: #3/4x-1/4 < x-3#

Multiply both sides by #4# to remove the fractions.

#cancel(4)(3x)/(cancel(4))-1/cancel(4) < 4(x-3)#

Simplify.

#3x-1 < 4x-12#

Subtract #4x# from both sides.

#3x-1-4x < -12#

Simplify.

#-x-1 < -12#

Add #1# to both sides.

#-x < -12+1#

Simplify.

#-x< -11#

Multiply both sides by #-1#.

#x > 11#