How do you solve #\frac { 3} { 8} ( 14- x ) = - 3x + 6#?

1 Answer
Sep 8, 2017

To simplify equations like this, you need to get rid of the nasty fractions first. Then things will start to fall into place.

#x=2/7#

Explanation:

We have: #3/8(14-x)=-3x+6#

To get rid of nasty fraction,

multiply everything by #8:to# #3(14-x)=-24x+48#

Clear out the parenthesis: #42-3x=-24x+48#

Accumulate like terms: #-3x+24x=48-42#

Combine like terms: #21x=6#

Answer: #x=6/21=2/7#

To check: #3/8(14-(2/7))=-3(2/7)+6#

Get rid of nasty fraction: #3(14-(2/7))=-24(2/7)+48#

Clear out the parenthesis: #42-6/7=-48/7+48#

Accumulate like terms: #-6/7 +48/7=6#

Combine like terms: #42/7=6#

Get rid of nasty fraction: #6=6to# Oh yeah!