How do you solve #\frac { 3} { x + 2} + \frac { 4} { x - 4} = \frac { 5} { x ^ { 2} - 2x - 8}#?

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Answer 1 · 2018-04-04T16:39:40

#x=9/7#

#x^2-2x-8# factorises to #(x-4)(x+2)#

Multiply both sides by #(x-4)(x+2)#

#=># #3(x-4) +4(x+2)=5#

#=># #3x-12+4x+8=5#

#=>##7x-4=5#

#=>#7x=9#

#x=9/7#