How do you solve #\frac{3}{x} - \frac{1}{3x} = \frac{2}{3}#?

1 Answer
Jan 24, 2017

See the entire solution process below:

Explanation:

First, multiple each side of the equation by #color(red)(3x)# to eliminate the fractions and keep the equation balanced:

#color(red)(3x)(3/x - 1/(3x)) = color(red)(3x) xx 2/3#

#(color(red)(3x) xx 3/x) - (color(red)(3x) xx 1/(3x)) = color(red)(3x) xx 2/3#

#(color(red)(3)cancel(color(red)(x)) xx 3/color(red)(cancel(color(black)(x)))) - (cancel(color(red)(3)color(red)(x)) xx 1/color(red)(cancel(color(black)(3x)))) = cancel(color(red)(3))color(red)(x) xx 2/color(red)(cancel(color(black)(3)))#

#(3 xx 3) - 1 = (x xx 2)#

#9 - 1 = 2x#

#8 = 2x#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#8/color(red)(2) = (2x)/color(red)(2)#

#4 = (color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2))#

#4 = x#

#x = 4#