How do you solve #\frac{32}{d - 2} = 10#?

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Answer 1 · 2018-03-12T03:01:54

#d=5.2#

#(32)/(d-2)=10# (Multiply both sides by #d-2#)

#32=10(d-2)# (Distribute 10)

#32=10d-20# (Add 20 to both sides)

#52=10d# (Divide both sides by 10)

#5.2=d#

Check the answer by plugging it back into the original equation

#(32)/(5.2-2)=10#

#(32)/(3.2) = 10#

#10=10#

Answer 2 · 2018-03-12T03:04:17

#d=26/5#

#32/(d-2)=10#

Start with cross multiply

#10(d - 2) = 32#

Distribute

#(10)(d) + (10)(-2) = 32#

#10d - 20 = 32#

Subtract #20# on both sides

#10d - 20 + 20 = 32 + 20#

#10d =52#

Divide both sides by #10#

#(cancel(10)d)/cancel10=52/10#

#d=26/5#