Question

How do you solve `\frac { 3k + 7} { 4} - 6= 10`?

Answer 1

`k=19`

Explanation:

`(3k+7)/4-6=10`

`(3k+7)/4=10+6`

`(3k+7)/4=16`

`3k+7=16*4`

`3k+7=64`

`3k=64-7`

`3k=57`

`k=57/3`

`k=19`