How do you solve #\frac { 47} { 8} x + 17= 13x - 12#?

1 Answer
Mar 11, 2017

See the entire solution process below:

Explanation:

First, subtract #color(red)(47/8x)# and add #color(red)(12)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#47/8x + 17 - color(red)(47/8x) + color(red)(12) = 13x - 12 - color(red)(47/8x) + color(red)(12)#

#47/8x - color(red)(47/8x) + 17 + color(red)(12) = 13x - color(red)(47/8x) - 12 + color(red)(12)#

#0 + 29 = (8/8 xx 13x) - color(red)(47/8x) - 0#

#29 = 104/8x - color(red)(47/8x)#

#29 = 57/8x#

Now, multiply each side of the equation by #color(red)(8/57)# to solve for #x# while keeping the equation balanced:

#color(red)(8/57) xx 29 = color(red)(8/57) xx 57/8x#

#232/57 = x#

#x = 232/57#