How do you solve #\frac { 5k } { 2} = 3k + 5#?

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Answer 1 · 2016-11-15T01:21:22

#k = -10#

Step 1) Multiple each side of the equation by #2# to eliminate the fraction and keep the equation balanced:

#(5k)/2 * 2 = 2 * (3k + 5)#

#5k * 2/2 = (2*3k) + (2*5)#

#5k = 6k + 10#

Step 2)

Solve for #k# while keeping the equation balanced:

#5k - 5k - 10 = 6k + 10 - 5k - 10#

#-10 = 6k - 5k#

#k = -10#