How do you simplify #\frac { 5r - 7} { r - 3} - \frac { 4r + 5} { r - 3}#?

1 Answer
EZ as pi
Mar 13, 2017

#(r-12)/(r-3)#

Explanation:

When adding or subtracting fractions, you need a common denominator. In this case the denominators are already the same, so we can write the fractions as one fraction:

#(5r-7)/(r-3) - (4r+5)/(r-3)#

#=(5r-7-(4r+5))/(r-3)" "larr# multiply the bracket by #-1#

#= (5r-7-4r-5)/(r-3)" "larr# simplify like terms

#=(r-12)/(r-3)#

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