How do you solve #\frac { 5x + 1} { x - 1} = \frac { 15x - 17} { 3x - 7}#?

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Answer 1 · 2018-05-12T06:57:33

no real solutions for x

#(5x+1)/(x-1)=(15x-17)/(3x-7)#

#(5x+1)/(x-1)xx(x-1)(3x-7)=(15x-17)/(3x-7)xx(x-1)(3x-7)#

#(5x+1)xx(3x-7)=(15x-17)xx(3x-7)#

#5x(3x-7)+1(3x-7)=15x(3x-7)-17(3x-7)#

#15x^2-35x+3x-7=45x^2-105-51x+119#

#15x^2-32x-7=45x^2-51x+14#

#0=(45-15)x^2+(-51+32)x+(14+7)#

#0=30x^2-19x+21#

find discriminant:
#Delta=(-19)^2-4xx30xx21=-2159#
#Delta<0#
#:.#no real solutions for x