How do you solve #\frac { 6} { 3x } + \frac { 1} { 2x } = - \frac { 1} { 6}#?

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Answer 1 · 2018-05-10T16:48:33

#x = 0 or -15#

As per the given question, we have

#6/(3x) + 1/(2x) = -1/6#

#:. (12x + 3x)/ (6x^2) = -1/6#

#:. 15x = 6x^2 xx (-1/6)#

#:. 15x = cancel6x^2 xx (-1/cancel6)#

#:. 15x = -x^2#

#:. x^2 + 15x = 0#

#:. x(x + 15) = 0#

#:. x = 0 or x = -15#

Hence, the answer.