How do you solve #-\frac { 6} { x } = - 9#?

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Answer 1 · 2017-02-11T22:56:41

#x = 2/3#

To solve for the variable #x# in the equation #-6/x = -9#

Begin by multiplying by #x# on both sides
#cancelx (-6/cancelx) =(-9)x#

#-6 = -9x#

Now divide by #-9# on both sides to isolate the variable.

#(cancel-6)/(cancel-9) = (cancel(-9)x)/(cancel(-9))#

#6/9 = x#

Now reduce for the solution.

#2/3 =x#

Answer 2 · 2017-02-15T19:36:24

#2/3#

#-6/x=-9#

#:.-6/x=-9/1#

cross multiply

#:.-9x=-6#

multiply both sides by#-1#

#-1 xx -9x=-6 xx -1#

#:.9x=6#

#:.x=cancel6^2/cancel9^3#

#:.x=2/3#