How do you solve #-\frac { 6} { y - 2} = - 5#?
1 Answer
Feb 18, 2017
Explanation:
One method is to multiply both sides of the equation by the denominator of the single fraction. That is (y -2)
#cancel((y-2))^1xx-6/cancel((y-2))^1=-5(y-2)#
#rArr-6=-5(y-2)# distribute the bracket.
#-6=-5y+10# subtract 10 from both sides.
#-6-10=-5ycancel(+10)cancel(-10)#
#rArr-5y=-16# To solve for y, divide both sides by - 5
#(cancel(-5) y)/cancel(-5)=(-16)/(-5)#
#rArry=16/5#
#color(blue)"As a check"# Substitute this value into the left side of the equation and if it equals the right side then it is the solution.
#-6/(16/5-2)=-6/(16/5-10/5)#
#color(white)(xxxxxxx)=-6/(6/5)#
#color(white)(xxxxxxx)=-cancel(6)^1xx5/cancel(6)^1#
#color(white)(xxxxxxx)=-5#
#rArry=16/5" is the solution"#