How do you solve #\frac { 7- 2y } { 4} = 2y + 3#?

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Answer 1 · 2018-03-20T21:29:12

#y=-1/2#

We can start by getting rid of the denominator of #4# by multiplying both sides by #4#. We get:

#cancel4((7-2y)/cancel4)=4(2y+3)#

#=>7-2y=8y+12#

Next, we can add #2y# to both sides to get:

#7=10y+12#

Our next step would be to subtract #12# from both sides. We get:

#10y=-5#

Dividing both sides by #10#, we get:

#y=-1/2#