How do you solve #\frac { 7} { 6} = \frac { 2} { p - 2}#?

1 Answer
Apr 8, 2017

See the entire solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(6)(color(blue)(p - 2))# to eliminate the fractions while keeping the equation balanced. #color(red)(6)(color(blue)(p - 2))# is the Lowest Common Denominator of the two fractions:

#color(red)(6)(color(blue)(p - 2)) xx 7/6 = color(red)(6)(color(blue)(p - 2)) xx 2/(p - 2)#

#cancel(color(red)(6))(color(blue)(p - 2)) xx 7/color(red)(cancel(color(black)(6))) = color(red)(6)cancel((color(blue)(p - 2))) xx 2/color(blue)(cancel(color(black)((p - 2)))#

#7(p - 2) = 12#

#(7 xx p) - (7 xx 2) = 12#

#7p - 14 = 12#

Next, add #color(red)(14)# to each side of the equation to isolate the #p# term while keeping the equation balanced:

#7p - 14 + color(red)(14) = 12 + color(red)(14)#

#7p - 0 = 26#

#7p = 26#

Now, divide each side of the equation by #color(red)(7)# to solve for #p# while keeping the equation balanced:

#(7p)/color(red)(7) = 26/color(red)(7)#

#(color(red)(cancel(color(black)(7)))p)/cancel(color(red)(7)) = 26/7#

#p = 26/7#