How do you solve #\frac { 7} { x - 3} - \frac { 6} { x + 1} = 1#?
1 Answer
Mar 18, 2017
x=7, -4
Explanation:
-
Find the gcf of the fractions which is (x-3)(x+1)
7(x+1) and 6(x-3) -
Subtract the two fractions.
#(7x+7-(6x-18))/((x-3)(x+1))#
3.Multiply (x-3)(x+1) to get rid of the fractions.
x+25= (x-3)(x+1)
x+25=
- Bring all the terms to one side
#x^2# -3x-28=0
5.Solve the equation (I'm assuming you know how to solve quadratic equations)
(x-7)(x+4)=0
x-7=0 x+4=0
x=7 x= -4
ANSWER: x=7, -4