First, multiply each side of the equation by #color(red)(20)/color(blue)(8)# to isolate the terms on one side of the equation while keeping the equation balanced:
#color(red)(20)/color(blue)(8) xx 8/20 = color(red)(20)/color(blue)(8) xx 32/n#
#cancel(color(red)(20))/cancel(color(blue)(8)) xx color(blue)(cancel(color(black)(8)))/color(red)(cancel(color(black)(20))) = color(red)(20)/cancel(color(blue)(8)) xx (color(blue)(cancel(color(black)(32)))4)/n#
#1 = 80/n#
Now, multiply each side of the equation by #color(red)(n)# to solve for #n# while keeping the equation balanced:
#color(red)(n) xx 1 = color(red)(n) xx 80/n#
#n = cancel(color(red)(n)) xx 80/color(red)(cancel(color(black)(n)))#
#n = 80#