How do you solve #|\frac{8x + 8}{4} | >=8#?

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Answer 1 · 2016-10-10T11:43:37

#S=(-oo;-5] vv [3;+oo)#

This inequality is equivalent to the following:

#(8x+8)/4<=-8 or (8x+8)/4>=8#

that's

#2x+2<=-8 or 2x+2>=8#

#2x<=-10 or 2x>=6#

#x<=-5 or x>=3#

that's

#S=(-oo;-5] vv [3;+oo)#