How do you solve #\frac { a - 2} { 4} = 4- \frac { 2a - 1} { 2}#?

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Answer 1 · 2018-01-18T18:49:44

#a=4#

okay, so lets start off by multiplying all the terms by 4.

#((a−2)/4)*4 =4*4− ((2a−1)/2)*4#

#a−2 = 16 − (2a−1)*2#

#a−2 = 16 − 4a+2#

soo, now its in a simpler form:)

#a−2 = 18 − 4a#

#5a = 20#

#a = 4#

Verification:-
LHS =>
#((a−2)/4)#
#=((4−2)/4)#
#=2/4#
#=1/2#

RHS =>
#4− ((2a−1)/2)#
#=4− ((2(4)−1)/2)#
#=8/2−((8-1)/2)#
#=8/2−7/2#
#=1/2#
Hence since LHS=RHS, its is verified.!

-Sahar