How do you solve #\frac { b } { 6} - 32< - 42#?

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Answer 1 · 2017-02-03T00:28:00

See the entire solution process below:

First, add #color(red)(32)# to each side of the inequality to isolate the #b# term while keeping the inequality balanced:

#b/6 - 32 + color(red)(32) < -42 + color(red)(32)#

#b/6 - 0 < -10#

#b/6 < -10#

Now, multiply each side of the inequality by #color(red)(6)# to solve for #b# while keeping the inequality balanced:

#color(red)(6) xx b/6 < color(red)(6) xx -10#

#cancel(color(red)(6)) xx b/color(red)(cancel(color(black)(6))) < -60#

#b < -60#