# How do you solve \frac { k + 1} { 3} = \frac { k - 2} { 6}?

Oct 21, 2016

$k = - 4$

#### Explanation:

$\frac{k + 1}{3} = \frac{k - 2}{6}$

Multiply both sides by 6 and simplify.

$6 \times \frac{k + 1}{3} = 6 \times \frac{k - 2}{6}$

$2 \left(k + 1\right) = k - 2$

$2 k + 2 = k - 2$

Subtract $k$ from both sides.

$k + 2 = - 2$

Subtract $2$ from both sides.

$k = - 2 - 2 = - 4$

$\therefore k = - 4$