How do you solve #\frac { k - 4} { 12} = - 1#?

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Answer 1 · 2017-03-03T04:45:02

See the entire solution process below:

First, multiply each side of the equation by #color(red)(12)# to eliminate the fraction while keeping the equation balanced:

#color(red)(12)((k - 4)/12) = color(red)(12) xx -1#

#cancel(color(red)(12))((k - 4)/color(red)(cancel(color(black)(12)))) = -12#

#k - 4 = -12#

Now, add #color(red)(4)# to each side of the equation to solve for #k# while keeping the equation balanced:

#k - 4 + color(red)(4) = -12 + color(red)(4)#

#k - 0 = -8#

#k = -8#