Question

How do you solve `\frac { p ^ { 2} - 2} { 3p - 6} - \frac { p } { 3} = \frac { 2} { p - 2}`?

Answer 1

Solution: `p =4`

Explanation:

`(p^2-2)/(3p-6) - p/3 = 2/(p-2)` or

`(p^2-2)/(3(p-2)) - p/3 = 2/(p-2)`. Mutiplying by `3(p-2)` on both

sides we get , `(p^2-2) - p(p-2) = 6` or

`cancel(p^2) -2- cancel(p^2)+2p =6 or 2p =8 or p =4`

Solution: `p =4` [Ans]