How do you solve #\frac { w+ 3} { 2} < - 8#?

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Answer 1 · 2018-03-11T13:19:44

See a solution process below:

First, multiply each side of the inequality by #color(red)(2)# to eliminate the fraction while keeping the inequality balanced:

#color(red)(2) xx (w + 3)/2 < color(red)(2) xx -8#

#cancel(color(red)(2)) xx (w + 3)/color(red)(cancel(color(black)(2))) < -16#

#w + 3 < -16#

Now, subtract #color(red)(3)# from each side of the inequality to solve for #w# while keeping the inequality balanced:

#w + 3 - color(red)(3) < -16 - color(red)(3)#

#w + 0 < -19#

#w < -19#