How do you solve #\frac { - x ^ { 2} + 14x - 13} { 5x - 3x ^ { 2} } = 0#?

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Answer 1 · 2017-11-28T11:21:19

#x=1 or 13#

#(-x^2+14x-13)/(5x-3x^2)=0#

Multiply both sides by #(5x-3x^2)#,

#-x^2+14x-13=0#

Multiply both sides by #-1#,

#x^2-14x+13=0#

Factorise,

#(x-13)(x-1)=0#
#x=1 or 13#