How do you solve #\frac { x + 2} { 3x } + \frac { x - 2} { 2x } = 3#?

1 Answer
Nov 28, 2016

#x = -2/13#

Explanation:

Step 1) Get each fraction over a common denominator, in this case #6x# by multiplying each fraction by the appropriate for of #1# in order to be able to add the fractions:

#(2/2) * (x+2)/(3x) + (3/3)*(x - 2)/(2x) = 3#

#(2x + 4)/(6x) + (3x - 6)/(6x) = 3#

#(2x + 4 + 3x - 6)/(6x) = 3#

#(5x - 2)/(6x) = 3#

Step 2) Multiply each side of the equation by #6x# to eliminate the fraction and keep the equation balanced:

#(6x*(5x - 2))/(6x) = 3*6x#

#5x - 2 = 18x#

Step 3) Solve for #x# using the necessary mathematics while keeping the equation balanced:

#5x - 5x - 2 = 18x - 5x#

#0 - 2 = 13x#

#-2 = 13x#

#-2/13 = (13x)/13#

#x = -2/13#