How do you solve #\frac{x + 2}{x - 5} \leq 1#?

1 Answer
Nov 14, 2017

#x < 5#

Explanation:

Given
#color(white)("XXX")(x+2)/(x-5) <=1#

If
#{:((x-5)" is positive",color(white)("XXX"),(x-5)" is zero",color(white)("xxx"),(x-5)"is negative"), (x+2 <=x-5,,"undefined",,x+2 >= x-5), (2 <= -5,,,,2>=-5), ("never true",,,,"always true") :}#

Therefore #(x-5)# is neagative
#color(white)("XXXXXXXXXXXXX")rarr x < 5#