How do you solve #\frac { ( x + 3) } { ( 2x - 1) } - \frac { ( 5x - 1) } { ( 4x + 7) } = 0#?

1 Answer
Sonnhard
Jun 18, 2018

#x=5# or # x=-2/3#

Explanation:

It must be
#xne 1/2# and #xne -7/4#
so we get by cross multiplication

#(x+3)(4x+7)=(5x-1)(2x-1)#
multiplying out we get

#4x^2+12x+7x+21=10x^2-2x-5x+1#
combining like terms

#0=6x^2-26x-20#
solving this by the quadratic formula
#x=5#
or
#x=-2/3#

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