How do you solve #\frac { x- 3} { 3} + \frac { x + 2} { 2} = 34#?

1 Answer
May 30, 2017

#x=204/5##""or"##40 4/5#

Explanation:

Solve:

#(x-3)/3+(x+2)/2=34#

Multiply both sides by the GCF #6#.

#(color(red)cancel(color(black)(6^2))(x-3))/3+(color(red)cancel(color(black)(6^3))(x+2))/2=34xx6#

Simplify.

#2(x-3)+3(x+2)=204#

Expand using the distributive property: #a(b+c)=ab+ac#

#2x-6+3x+6=204#

Simplify.

#2x-color(red)cancel(color(black)(6))+3x+color(red)cancel(color(black)(6))=204#

Simplify.

#2x+3x=204#

#5x=204#

Divide both sides by #5#.

#(5x)/5=204/5#

Simplify.

#(color(red)cancel(color(black)(5^1))x)/color(red)cancel(color(black)(5^1))=204/5#

#x=204/5#

You can convert #204/5# to a mixed fraction by dividing #204# by #5#. The whole number is the quotient and the remainder is the numerator over the denominator of #5#.

#204-:5=40# with a remainder of #4#

As a mixed fraction, #x=40 4/5#.