How do you solve #\frac { x } { 4} - 1\leq - 3#?

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Answer 1 · 2017-08-04T22:11:36

See a solution process below

First, add #color(red)(1)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#x/4 - 1 + color(red)(1) <= -3 + color(red)(1)#

#x/4 - 0 <= -2#

#x/4 <= -2#

Now, multiply each side of the equation by #color(red)(4)# to solve for #x# while keeping the equation balanced:

#color(red)(4) xx x/4 <= color(red)(4) xx -2#

#cancel(color(red)(4)) xx x/color(red)(cancel(color(black)(4))) <= -8#

#x <= -8#