How do you solve #\frac{x}{4} + 2\leq 3#?

1 Answer
Sirach
Jun 20, 2018

  1. Find the LCD of the equation. This being #4#.

  2. Multiply each term of the equation by the LCD. (In case of a negative LCD, flip the sign.)
    #x/4 + 2 ≤ 3# becomes #x+8 ≤12#

  3. Evaluate the inequality.
    #x+8 ≤12#
    #x ≤4#

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