How do you solve #\frac{x}{4} + 2\leq 3#?

1 Answer
Sirach
Jun 20, 2018

  1. Find the LCD of the equation. This being #4#.

  2. Multiply each term of the equation by the LCD. (In case of a negative LCD, flip the sign.)
    #x/4 + 2 ≤ 3# becomes #x+8 ≤12#

  3. Evaluate the inequality.
    #x+8 ≤12#
    #x ≤4#

Related questions
Impact of this question
1002 views around the world
You can reuse this answer
Creative Commons License