How do you solve #\frac { x } { 4} + 4= 11#?

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Answer 1 · 2018-03-20T10:20:43

See a solution process below:

First, subtract #color(red)(4)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#x/4 + 4 - color(red)(4) = 11 - color(red)(4)#

#x/4 + 0 = 7#

#x/4 = 7#

Now, multiply each side of the equation by #color(red)(4)# to solve for #x# while keeping the equation balanced:

#color(red)(4) xx x/4 = color(red)(4) xx 7#

#cancel(color(red)(4)) xx x/color(red)(cancel(color(black)(4))) = 28#

#x = 28#