Multiply each side of the equation by #color(red)(21)# to eliminate the fractions while keeping the equation balanced. We chose #color(red)(21)# because it is the lowest common denominator of the two fractions:
#color(red)(21) xx (x + 5)/7 = color(red)(21) xx 5/3#
#cancel(color(red)(21))3 xx (x + 5)/color(red)(cancel(color(black)(7))) = cancel(color(red)(21))7 xx 5/color(red)(cancel(color(black)(3)))#
#3(x + 5) = 7 xx 5#
#(3 xx x) + (3 xx 5) = 35#
#3x + 15 = 35#
Next, subtract #color(red)(15)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#3x + 15 - color(red)(15) = 35 - color(red)(15)#
#3x + 0 = 20#
#3x = 20#
Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:
#(3x)/color(red)(3) = 20/color(red)(3)#
#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 20/3#
#x = 20/3#
