How do you solve #\frac { ( - x + 8) } { 2} \geq 3#?

1 Answer
Sep 25, 2017

See a solution process below

Explanation:

First, multiply each side of the inequality by #color(red)(2)# to eliminate the fraction while keeping the inequality balanced:

#color(red)(2) xx (-x + 8)/2 >= color(red)(2) xx 3#

#cancel(color(red)(2)) xx (-x + 8)/color(red)(cancel(color(black)(2))) >= 6#

#-x + 8 >= 6#

Next, subtract #color(red)(8)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#-x + 8 - color(red)(8) >= 6 - color(red)(8)#

#-x + 0 >= -2#

#-x >= -2#

Now, multiply each side of the inequality by #color(blue)(-1)# to solve for #x# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:

#color(blue)(-1) xx -x color(red)(<=) color(blue)(-1) xx -2#

#x color(red)(<=) 2#