How do you solve #\frac { y + 1} { 2} = - 2( y + 1)#?

1 Answer
Nov 23, 2016

#y = -1#

Explanation:

First, multiple each side of the equation by #2# to eliminate the fraction which will make the problem easier to work with as well as keeping the equation balanced:

#2 (y + 1)/2 = 2 * -2(y + 1)#

#cancel(2) (y + 1)/cancel(2) = -4(y + 1)#

#y + 1= -4(y + 1)

Next expand the term in parenthesis:

#y + 1 = -4y - 4#

Now perform the necessary mathematics to isolate the #y# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

#y + 1 - 1 + 4y = -4y - 4 - 1 + 4y#

#y + 4y = -5#

#5y = -5#

Last, divide each side of the equation by #5# to solve for #y# and keep the equation balanced:

#(5y)/5 = (-5)/5#

#(cancel(5)y)/cancel(5) = (-5)/5#

#y = -1#