How do you solve #\frac{y}{3}+10=65#?

1 Answer
Nov 22, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(10)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#y/3 + 10 - color(red)(10) = 65 - color(red)(10)#

#y/3 + 0 = 55#

#y/3 = 55#

Now, multiply each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#color(red)(3) xx y/3 = color(red)(3) xx 55#

#cancel(color(red)(3)) xx y/color(red)(cancel(color(black)(3))) = 165#

#y = 165#