How do you solve #\frac { z } { 3} + 4= \frac { z } { 2} + 8#?

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Answer 1 · 2017-09-05T03:37:30

#z = -24#

#z/3 + 4 = z/2 + 8#

LCM of #3 and 2 = 6#

Multiply via their LCM

#cancel6^2(z/cancel3) + 6(4) = cancel6^3(z/cancel2) + 6(8)#

#2(z) + 24 = 3(z) + 48#

#2z + 24 = 3z + 48#

Collect like terms

#2z - 3z = 48 - 24#

#-z = 24#

#:. z = -24#