Question

How do you solve `g/27=2/9`?

Answer 1

`g = 6`

Explanation:

You are only one step away from isolating the variable,`g`, on the left.

`g/27 = 2/9" "larr` multpily by 27 to cancel the denominator

`(color(red)(27 xx)g)/27 = (color(red)(27 xx)2)/9" "larr` multiply on BOTH sides

`(color(red)(cancel27 xx)g)/cancel27 = (color(red)(cancel27^3 xx)2)/cancel9" "larr " isolate " g`

`rarr g = 6`