How do you solve #g/27=2/9#?

1 Answer
Sep 29, 2016

Answer:

#g = 6#

Explanation:

You are only one step away from isolating the variable,#g#, on the left.

#g/27 = 2/9" "larr# multpily by 27 to cancel the denominator

#(color(red)(27 xx)g)/27 = (color(red)(27 xx)2)/9" "larr# multiply on BOTH sides

#(color(red)(cancel27 xx)g)/cancel27 = (color(red)(cancel27^3 xx)2)/cancel9" "larr " isolate " g#

#rarr g = 6#