Question

How do you solve `j^ { 2} + 12j = 0`?

Answer 1

`j=0` or `j=-12`

Explanation:

First, take `j` common from LHS,
`rArr j(j+12)=0`
By zero product rule,
Either, `j=0` Or,`(j+12)=0`
So, either `j=0` or `j=-12`

That's it,
Hope this helps :)