How do you solve j+j+j+j+j+j+j?

Don't understand what this means its from an Algebra worksheet

1 Answer
May 6, 2018



There are 7 of them.
If you imagine the j was a tin of beans(!) then you would have 7 tins of beans. If the terms are the same you can add/subtract them.
If you have # j+j+ j^2+j+j+j=j^2+5j#
You don't add the ones with different powers together #j and j^2# are the same letter but different terms, as different as #x and y#.
Hope this helps a bit.