How do you solve #k+ 1= 3k - 1#?

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Answer 1 · 2018-05-09T18:01:20

#k = 1#

As per the question, we have

#k + 1 = 3k -1#

#:. 1 + 1 = 3k - k#

#:. 2k = 2#

#:. k = 2/2#

#:. k =1#

#:. k = 1# is the solution to this problem.

Answer 2 · 2018-05-09T18:14:20

#k = 1#

#k + 1 = 3k - 1#

Subtract 1k from each side, remember what you do on one side you do on the other.
#1 = 2k - 1#

Add 1 to each side.
#2 = 2k#

You can switch them:
#2k = 2#

Now divide each by 2.
#(2k)/2 = 2/2#

#2/2# is the same thing as #1/1# which is equal to one:

#k = 1#