Question

How do you solve `ln(3x-6)=1`?

Answer 1

`x=(e+6)/3`.

Explanation:

`a^(log_ax)=x` and `log_aa^x=x`, since exponents and logs are inverse operations.

Since the base of the natural logarithm is `e`, we can do `e` to the power of both sides to undo the natural log on the left hand side.

`e^(ln(3x-6))=e^1`.

This simplifies to `3x-6=e`.

So `x=(e+6)/3`.