How do you solve $\ln ( 4t ) - \ln ( 3t ) = 2$ ?

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Answer 1 · 2018-04-21T01:59:46

There is no solution for this equation.

Log law states:
$log_e (x/y) = log_e (x) - log_e (y)$

Therefore
$ln((4t)/(3t))!=2$
$ln(4/3)!=2$
Error LHS $!=$ RHS

How do you solve \ln ( 4t ) - \ln ( 3t ) = 2\ln ( 4t ) - \ln ( 3t ) = 2?