Question

How do you solve `Ln(5x-4)=ln2+ln(x+1)`?

Answer 1

`x=2`

Explanation:

Taking `ln(5x-4) = ln(2)+ln(x+1)` or equivalently `ln(5x-4)-ln(2*(x+1))=0` or `ln[(5x-4)/(2(x+1))]= ln(1)` then results in
`(5x-4)/(2(x+1))=1` or `5x-4=2(x+1)` and finally `x = 2`