How do you solve #\ln 9k - 5= - 3#?
1 Answer
Jun 26, 2017
Explanation:
#"using the "color(blue)"law of logarithms"#
#• log_bx=nhArrx=b^n#
#rArrlog_e9k=2#
#rArr9k=e^2#
#rArrk=e^2/9~~0.82" to 2 dec. places"#
