Question

How do you solve `ln e^ln x - ln(x-2) = ln 8`?

Answer 1

`x=16/7`

Explanation:

`ln e^ln x - ln(x-2) = ln 8`

`=>ln x - ln(x-2) = ln 8`

`=>ln (x/(x-2) )= ln 8`

`=> (x/(x-2) )= 8`

`=>8x-16=x`

`=>7x=16=>x=16/7`