How do you solve $ln (e^{x} - 2) = 3$ $Ln(e^(x) - 2)=3$ ?

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How do you solve $ln (e^{x} - 2) = 3$ $Ln(e^(x) - 2)=3$ ?

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Answer 1 · 2016-07-19T13:55:41

to get rid of the $ln$ $ln$ just raise make it a power of $e$ $e$
$e^{x} - 2 = e^{3}$ $e^x-2=e^3$
then move over the 2
$e^{x} = e^{3} + 2$ $e^x=e^3+2$
now to get rid of $e$ $e$ you use $ln$ $ln$
$x = ln (e^{3} + 2)$ $x=ln(e^3+2)$

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How do you solve $ln (e^{x} - 2) = 3$ $Ln(e^(x) - 2)=3$ ?

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