How do you solve $ln (- m) = ln (m + 10)$ $ln(-m)=ln(m+10)$ ?

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Answer 1 · 2016-12-21T00:16:21

$m = - 5$ $m = -5$

Given:

$ln (- m) = ln (m + 10)$ $ln(-m) = ln(m+10)$

Take exponents of both sides to find:

$- m = e^{ln (- m)} = e^{ln (m + 10)} = m + 10$ $-m = e^(ln(-m)) = e^(ln(m+10)) = m+10$

Add $m - 10$ $m-10$ to both ends to get:

$- 10 = 2 m$ $-10 = 2m$

Divide both sides by $2$ $2$ and transpose to get:

$m = - 5$ $m = -5$

How do you solve ln(−m)=ln(m+10)ln(-m)=ln(m+10)?